(x)dx+ye^ydy=0

Lösung

(x) d x + y e^{y} d y = 0

y = W (\frac{- x ^{2} + c _{1}}{2 e}) + 1

Schritte zur Lösung

(x) d x + y e^{y} d y = 0

Solve separable ODE:

y = W (\frac{- x ^{2} + c _{1}}{2 e}) + 1

y = W (\frac{- x ^{2} + c _{1}}{2 e}) + 1

y^{^{'}} e^{x} + 2 x y = 0

y^{^{'}} = \frac{y}{x ^{2} + 1}

(x^{2} - 9) y^{^{'}} + x y = 0

y^{^{'}} = \frac{2 y ^{2}}{x ^{2}}

\frac{( 1 + y )}{1 - 2 y - y ^{2}} \frac{d y}{d x} = \frac{1}{x}