y^'=(2y^2)/(x^2)

Lösung

y^{^{'}} = \frac{2 y ^{2}}{x ^{2}}

y = - \frac{x}{- 2 + c _{1} x}

Schritte zur Lösung

y^{'} (x) = \frac{2 y ^{2}}{x ^{2}}

Solve separable ODE:

y = - \frac{x}{- 2 + c _{1} x}

y = - \frac{x}{- 2 + c _{1} x}

\frac{( 1 + y )}{1 - 2 y - y ^{2}} \frac{d y}{d x} = \frac{1}{x}

\frac{d r}{d t} = 0.1872 \cdot r

\frac{1 + x ^{2}}{1 + y} \frac{d y}{d x} = - x

y^{^{'}} = (x^{2} - 4) (3 y + 2)

(x^{2} + 2 x - 1) \frac{d y}{d x} - (x + 1) y = x + 1