integral from 0 to 2pi of 9

Lösung

\int_{0}^{2 π} 9 d x

18 π

Dezimale

56.54866 \dots

Schritte zur Lösung

\int_{0}^{2 π} 9 d x

Integral einer Konstanten :

\int a d x = a x

= [9 x]_{0}^{2 π}

Berechne die Grenzen:

18 π

= 18 π

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