integral from-2 to 1 of 2x^2-x^4-x^3

Lösung

\int_{- 2}^{1} 2 x^{2} - x^{4} - x^{3} d x

\frac{63}{20}

Dezimale

3.15

Schritte zur Lösung

\int_{- 2}^{1} 2 x^{2} - x^{4} - x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x - \int_{- 2}^{1} x^{4} d x - \int_{- 2}^{1} x^{3} d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} x^{4} d x = \frac{33}{5}

\int_{- 2}^{1} x^{3} d x = - \frac{15}{4}

= 6 - \frac{33}{5} - (- \frac{15}{4})

Vereinfache

6 - \frac{33}{5} - (- \frac{15}{4}) : \frac{63}{20}

= \frac{63}{20}

\int_{1}^{4} (- 2 x^{2} + 2 x)^{2} d x

\int_{0}^{1} \frac{2 x}{( x + 1 ) ^{2}} d x

\int_{0}^{3} 4 - x^{2} d x

\int_{x}^{a} 2^{l n (t)} d t

\int_{0}^{1} (e^{x})^{3} d x