integral from x to pi-x of sin(x+y)

Lösung

\int_{x}^{π - x} sin (x + y) d y

1 + cos (2 x)

Schritte zur Lösung

\int_{x}^{π - x} sin (x + y) d y

Wende U-Substitution an

= \int_{2 x}^{π} sin (u) d u

Nutze das gemeinsame Integral :

\int sin (u) d u = - cos (u)

= [- cos (u)]_{2 x}^{π}

Berechne die Grenzen:

1 + cos (2 x)

= 1 + cos (2 x)

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