integral from 2 to 4 of-t^2+6t-8

Lösung

\int_{2}^{4} - t^{2} + 6 t - 8 d t

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{2}^{4} - t^{2} + 6 t - 8 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{2}^{4} t^{2} d t + \int_{2}^{4} 6 t d t - \int_{2}^{4} 8 d t

\int_{2}^{4} t^{2} d t = \frac{56}{3}

\int_{2}^{4} 6 t d t = 36

\int_{2}^{4} 8 d t = 16

= - \frac{56}{3} + 36 - 16

Vereinfache

- \frac{56}{3} + 36 - 16 : \frac{4}{3}

= \frac{4}{3}

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