x^{'''}+x^{''}=0

Lösung

x^{^{'''}} + x^{^{''}} = 0

x = c_{1} e^{- t} + c_{2} + c_{3} t

Schritte zur Lösung

x^{'''} (t) + x^{''} (t) = 0

Solve linear ODE:

x = c_{1} e^{- t} + c_{2} + c_{3} t

x = c_{1} e^{- t} + c_{2} + c_{3} t

\int \frac{( x ^{2} + 1 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\int sin^{2} (5 x) cos^{2} (5 x) d x

d er i v a t i v e (t + 1)^{\frac{2}{3}} (3 t^{2} - 2)^{3}

\frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}})

3 e^{5 x} \frac{d y}{d x} = - 25 \frac{x}{y ^{2}}