integral from 0 to 1 of ax+bx^3

Lösung

\int_{0}^{1} a x + b x^{3} d x

\frac{a}{2} + \frac{b}{4}

Schritte zur Lösung

\int_{0}^{1} a x + b x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} a x d x + \int_{0}^{1} b x^{3} d x

\int_{0}^{1} a x d x = \frac{a}{2}

\int_{0}^{1} b x^{3} d x = \frac{b}{4}

= \frac{a}{2} + \frac{b}{4}

\int_{0}^{0.5} - 2 x + 1 d x

\int_{4}^{7} 6 x - 24 d x

\int_{- 2}^{1 \cdot 5} x^{2} - 1 d x

\int_{- 1}^{2} - x^{2} + 7 d x

\int_{- 1}^{1} \frac{1}{1 + y ^{2}} d y