integral from 0 to 0.5 of-2x+1

Lösung

\int_{0}^{0.5} - 2 x + 1 d x

0.25

Schritte zur Lösung

\int_{0}^{0.5} - 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{0.5} 2 x d x + \int_{0}^{0.5} 1 d x

\int_{0}^{0.5} 2 x d x = 0.25

\int_{0}^{0.5} 1 d x = 0.5

= - 0.25 + 0.5

Vereinfache

= 0.25

\int_{4}^{7} 6 x - 24 d x

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