integral from 0 to 0.9 of e^{-x}+1

Lösung

\int_{0}^{0.9} e^{- x} + 1 d x

1.49343 \dots

Schritte zur Lösung

\int_{0}^{0.9} e^{- x} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{0.9} e^{- x} d x + \int_{0}^{0.9} 1 d x

\int_{0}^{0.9} e^{- x} d x = 0.59343 \dots

\int_{0}^{0.9} 1 d x = 0.9

= 0.59343 \dots + 0.9

Vereinfache

= 1.49343 \dots

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