integral from-1 to 0 of 2y+2

Lösung

\int_{- 1}^{0} 2 y + 2 d y

1

Schritte zur Lösung

\int_{- 1}^{0} 2 y + 2 d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 2 y d y + \int_{- 1}^{0} 2 d y

\int_{- 1}^{0} 2 y d y = - 1

\int_{- 1}^{0} 2 d y = 2

= - 1 + 2

Vereinfache

= 1

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