integral from-2 to-1 of 1/((x+1)^2)

Lösung

\int_{- 2}^{- 1} \frac{1}{( x + 1 ) ^{2}} d x

divergiert

Schritte zur Lösung

\int_{- 2}^{- 1} \frac{1}{( x + 1 ) ^{2}} d x

Wende U-Substitution an

= \int_{- 1}^{0} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= [- \frac{1}{u}]_{- 1}^{0}

Berechne die Grenzen:

divergiert

= divergiert

\int_{1}^{2} x e^{5 x^{2}} d x

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\int_{- t}^{t} 1 - x^{2} - y^{2} d y

\int_{0}^{3} (4 x - 1)^{2} d x

\int_{0}^{1} x^{\frac{5}{2}} d x