What is the derivative of 1+5sin(x) ?

The derivative of 1+5sin(x) is 5cos(x)

What is the first derivative of 1+5sin(x) ?

The first derivative of 1+5sin(x) is 5cos(x)

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\frac{d}{d x} (1 + 5 sin (x))

5 cos (x)

Solution steps

\frac{d}{d x} (1 + 5 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (5 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (5 sin (x)) = 5 cos (x)

= 0 + 5 cos (x)

Simplify

= 5 cos (x)

\frac{d}{d x} (e^{a x} cos (b x))

\int_{1}^{2} \frac{( 3 x - 1 )}{3 x} d x

\frac{d}{d x} (sin (5 x) e^{3 x})

2 y^{^{'}} + 3 y = 0

\frac{\partial}{\partial x} (\frac{2}{2 x - 2 z + 1})

What is the derivative of 1+5sin(x) ?
The derivative of 1+5sin(x) is 5cos(x)
What is the first derivative of 1+5sin(x) ?
The first derivative of 1+5sin(x) is 5cos(x)