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Popular >

2y^'+3y=0

Solution

2 y^{^{'}} + 3 y = 0

Solution

y = e^{\frac{- 3 t + c _{1}}{2}}

Solution steps

2 y^{'} (t) + 3 y = 0

Solve separable ODE:

y = e^{\frac{- 3 t + c _{1}}{2}}

y = e^{\frac{- 3 t + c _{1}}{2}}

Popular Examples

(\partial)/(\partial x)(2/(2x-2z+1))

\frac{\partial}{\partial x} (\frac{2}{2 x - 2 z + 1})

derivative of x*sqrt(3x^2+5)derivative of

x \cdot 3 x^{2} + 5

area x^2,x,-1,1 area

x^{2}, x, - 1, 1

area x^2-2,x,-2,2 area

x^{2} - 2, x, - 2, 2

y^'=(4xy)/(2+x^2)

y^{^{'}} = \frac{4 x y}{2 + x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for 2y^'+3y=0 ?
The solution for 2y^'+3y=0 is y=e^{(-3t+c_{1})/2}