integral from x^2 to x^4 of sqrt(u)

Lösung

\int_{x^{2}}^{x^{4}} u d u

\frac{2 x ^{6} - 2 x ^{3}}{3}

Schritte zur Lösung

\int_{x^{2}}^{x^{4}} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{x^{2}}^{x^{4}}

Berechne die Grenzen:

\frac{2}{3} x^{6} - \frac{2}{3} x^{3}

= \frac{2}{3} x^{6} - \frac{2}{3} x^{3}

Vereinfache

= \frac{2 x ^{6} - 2 x ^{3}}{3}

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