What is laplacetransform 0.025sin((2pit)/(10)) ?

The answer to laplacetransform 0.025sin((2pit)/(10)) is (0.125pi)/(25s^2+pi^2)

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laplacetransform 0.025sin((2pit)/(10))

laplace transform

0.025 sin (\frac{2 π t}{10})

\frac{0.125 π}{25 s ^{2} + π ^{2}}

Solution steps

L {0.025 sin (\frac{2 π t}{10})}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 0.025 L {sin (\frac{2 π t}{10})}

L {sin (\frac{2 π t}{10})} : \frac{5 π}{25 s ^{2} + π ^{2}}

= 0.025 \cdot \frac{5 π}{25 s ^{2} + π ^{2}}

Refine

0.025 \frac{5 π}{25 s ^{2} + π ^{2}} : \frac{0.125 π}{25 s ^{2} + π ^{2}}

= \frac{0.125 π}{25 s ^{2} + π ^{2}}

\frac{d}{d x} (\frac{x}{( x - 2 ) ^{2}})

\int_{1}^{l n (8)} \int_{0}^{l n (y)} e^{x + y} d x d y

\frac{d y}{d x} = \frac{1}{4 x}

\int \frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}} d x

x^{4} - 9 x^{2}, x^{2} - 9, 0, 3

What is laplacetransform 0.025sin((2pit)/(10)) ?
The answer to laplacetransform 0.025sin((2pit)/(10)) is (0.125pi)/(25s^2+pi^2)