What is the derivative of x/((x-2^2)) ?

The derivative of x/((x-2^2)) is (-2-x)/((x-2)^3)

What is the first derivative of x/((x-2^2)) ?

The first derivative of x/((x-2^2)) is (-2-x)/((x-2)^3)

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\frac{d}{d x} (\frac{x}{( x - 2 ) ^{2}})

\frac{- 2 - x}{( x - 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{x}{( x - 2 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x - 2 ) ^{2} - \frac{d}{d x} ( ( x - 2 ) ^{2} ) x}{( ( x - 2 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x - 2)^{2}) = 2 (x - 2)

= \frac{1 \cdot ( x - 2 ) ^{2} - 2 ( x - 2 ) x}{( ( x - 2 ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x - 2 ) ^{2} - 2 ( x - 2 ) x}{( ( x - 2 ) ^{2} ) ^{2}} : \frac{- 2 - x}{( x - 2 ) ^{3}}

= \frac{- 2 - x}{( x - 2 ) ^{3}}

\int_{1}^{l n (8)} \int_{0}^{l n (y)} e^{x + y} d x d y

\frac{d y}{d x} = \frac{1}{4 x}

\int \frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}} d x

x^{4} - 9 x^{2}, x^{2} - 9, 0, 3

\int \frac{x}{x ^{2} + 64} d x

What is the derivative of x/((x-2^2)) ?
The derivative of x/((x-2^2)) is (-2-x)/((x-2)^3)
What is the first derivative of x/((x-2^2)) ?
The first derivative of x/((x-2^2)) is (-2-x)/((x-2)^3)