What is area y=e^x,y=e^{2x},x=0,x=ln(2) ?

The answer to area y=e^x,y=e^{2x},x=0,x=ln(2) is 1/2

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area y=e^x,y=e^{2x},x=0,x=ln(2)

area

y = e^{x}, y = e^{2 x}, x = 0, x = ln (2)

\frac{1}{2}

Decimal Notation

0.5

Solution steps

Apply the area formula:

\int_{0}^{l n (2)} e^{x} - e^{2 x} d x

Solve

\int_{0}^{l n (2)} e^{x} - e^{2 x} d x : \frac{1}{2}

The area is:

= \frac{1}{2}

\frac{x - ln ( 1 + x )}{x ^{2}}

f (x) = 4 x^{2} - 4 x + 1, at x = 0

\int 5^{2} - x^{2} d x

\frac{\partial}{\partial x} (x tan (x))

y = 3 x (a^{2} - x^{2})

What is area y=e^x,y=e^{2x},x=0,x=ln(2) ?
The answer to area y=e^x,y=e^{2x},x=0,x=ln(2) is 1/2