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Popular >

y^'=e^{-x}

Solution

y^{^{'}} = e^{- x}

Solution

y = - e^{- x} + c_{1}

Solution steps

y^{'} (x) = e^{- x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{- x} d x

\int e^{- x} d x = - e^{- x} + c_{1}

y = - e^{- x} + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-x} ?
The solution for y^'=e^{-x} is y=-e^{-x}+c_{1}