What is area y=2sin(x),y=2cos(x) ?

The answer to area y=2sin(x),y=2cos(x) is 4sqrt(2)

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area y=2sin(x),y=2cos(x)

area

y = 2 sin (x), y = 2 cos (x)

42

Decimal Notation

5.65685 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 2 sin (x) - 2 cos (x) ∣ d x

Solve

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 2 sin (x) - 2 cos (x) ∣ d x : 42

The area is:

= 42

3 x, x 1 8^{2} - x^{2}

\frac{\partial}{\partial y} (e^{6 x y} \cdot 6 x)

x \to 0 lim (\frac{8}{x} - \frac{8}{x ^{2} + x})

\int x^{2} - 6 xx d x

What is area y=2sin(x),y=2cos(x) ?
The answer to area y=2sin(x),y=2cos(x) is 4sqrt(2)