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Popular >

(\partial ^2)/(\partial x\partial y)(ln(4+x^2y^2))

Solution

\frac{\partial ^{2}}{\partial x \partial y} (ln (4 + x^{2} y^{2}))

Solution

\frac{16 x y}{( 4 + x ^{2} y ^{2} ) ^{2}}

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (ln (4 + x^{2} y^{2}))

\frac{\partial}{\partial x} (ln (4 + x^{2} y^{2})) = \frac{2 x y ^{2}}{4 + x ^{2} y ^{2}}

= \frac{\partial}{\partial y} (\frac{2 x y ^{2}}{4 + x ^{2} y ^{2}})

\frac{\partial}{\partial y} (\frac{2 x y ^{2}}{4 + x ^{2} y ^{2}}) = \frac{16 x y}{( 4 + x ^{2} y ^{2} ) ^{2}}

= \frac{16 x y}{( 4 + x ^{2} y ^{2} ) ^{2}}

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\int \frac{1}{x ( ln ( x ) + ln ^{2} ( x ) )} d x

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x \to 2 lim (7)

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\frac{d}{d t} (A t e^{t})

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n = 1 \sum \infty \frac{n}{1 - 7 n}

Frequently Asked Questions (FAQ)

What is (\partial ^2)/(\partial x\partial y)(ln(4+x^2y^2)) ?
The answer to (\partial ^2)/(\partial x\partial y)(ln(4+x^2y^2)) is (16xy)/((4+x^2y^2)^2)