integral from 2+cos(x) to x^2+1 of 1/x

Lösung

\int_{2 + c o s (x)}^{x^{2} + 1} \frac{1}{x} d x

ln x^{2} + 1 - ln ∣ 2 + cos (x) ∣

Schritte zur Lösung

\int_{2 + c o s (x)}^{x^{2} + 1} \frac{1}{x} d x

Nutze das gemeinsame Integral :

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{2 + c o s (x)}^{x^{2} + 1}

Berechne die Grenzen:

ln x^{2} + 1 - ln ∣ 2 + cos (x) ∣

= ln x^{2} + 1 - ln ∣ 2 + cos (x) ∣

\int_{0}^{4} x x^{2} + 3 d x

\int_{0}^{1} (x^{2} + 4) e^{3 x} d x

\int_{0}^{4} x x^{2} + 6 d x

\int_{0}^{1} x^{2} (2 + 2 x^{3})^{5} d x

\int_{0}^{3} x^{2} e^{x^{3}} d x