integral from 0 to 4 of xsqrt(x^2+6)

Lösung

\int_{0}^{4} x x^{2} + 6 d x

\frac{22 22}{3} - 26

Dezimale

29.49740 \dots

Schritte zur Lösung

\int_{0}^{4} x x^{2} + 6 d x

Wende U-Substitution an

= \int_{6}^{22} u^{2} d u

Wende die Potenzregel an

= [\frac{u ^{3}}{3}]_{6}^{22}

Berechne die Grenzen:

\frac{22 22}{3} - 26

= \frac{22 22}{3} - 26

\int_{0}^{1} x^{2} (2 + 2 x^{3})^{5} d x

\int_{0}^{3} x^{2} e^{x^{3}} d x

\int_{0}^{π} - 2 cos^{2} (x) sin (x) d x

\int_{0}^{1} 3 cos (\frac{π x}{2}) d x

\int_{0}^{1} x^{2} (1 + 2 x^{3})^{3} d x