What is the solution for (d^2x)/(dt^2)=-kx ?

The solution for (d^2x)/(dt^2)=-kx is x=c_{1}cos(sqrt(k)t)+c_{2}sin(sqrt(k)t)

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(d^2x)/(dt^2)=-kx

\frac{d ^{2} x}{d t ^{2}} = - k x

x = c_{1} cos (k t) + c_{2} sin (k t)

Solution steps

\frac{d ^{2} x}{d t ^{2}} = - k x (t)

Solve linear ODE:

x = c_{1} cos (k t) + c_{2} sin (k t)

x = c_{1} cos (k t) + c_{2} sin (k t)

\frac{d}{d x} ((8 x^{2} - 2 x) (5 x + 9))

y^{^{''}} - 4 y^{^{'}} + 53 y = 0

\frac{d}{d x} ((x^{5} + 1)^{6})

x \to 5 lim (\frac{x}{x + 1})

I nb x^{4}

What is the solution for (d^2x)/(dt^2)=-kx ?
The solution for (d^2x)/(dt^2)=-kx is x=c_{1}cos(sqrt(k)t)+c_{2}sin(sqrt(k)t)