What is the derivative of sqrt(t^2+1) ?

The derivative of sqrt(t^2+1) is t/(sqrt(t^2+1))

What is the first derivative of sqrt(t^2+1) ?

The first derivative of sqrt(t^2+1) is t/(sqrt(t^2+1))

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derivative of

t^{2} + 1

\frac{t}{t ^{2} + 1}

Solution steps

\frac{d}{d t} (t^{2} + 1)

Apply the chain rule:

\frac{1}{2 t ^{2} + 1} \frac{d}{d t} (t^{2} + 1)

= \frac{1}{2 t ^{2} + 1} \frac{d}{d t} (t^{2} + 1)

\frac{d}{d t} (t^{2} + 1) = 2 t

= \frac{1}{2 t ^{2} + 1} \cdot 2 t

Simplify

\frac{1}{2 t ^{2} + 1} \cdot 2 t : \frac{t}{t ^{2} + 1}

= \frac{t}{t ^{2} + 1}

\frac{d}{d x} (5 + 3 x)

\int \frac{5 x - 3}{x ^{2} + 4} d x

\int \frac{1}{x ^{2} + 4 x + 13} d x

x \to π lim (ln ∣ cos (x) - 7 ∣)

\int_{0}^{\frac{π}{2}} cos^{7} (x) d x

What is the derivative of sqrt(t^2+1) ?
The derivative of sqrt(t^2+1) is t/(sqrt(t^2+1))
What is the first derivative of sqrt(t^2+1) ?
The first derivative of sqrt(t^2+1) is t/(sqrt(t^2+1))