2y^{''}+5y^'-3y=0

Lösung

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 3 t}

Schritte zur Lösung

2 y^{''} (t) + 5 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 3 t}

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 3 t}

\frac{\partial}{\partial y} (2 x y + z^{2})

\frac{\partial}{\partial x} (3 x ln (y) + y ln (z) - 2 x)

\int x (x + \frac{1}{x}) d x

\int x^{2} d x

x \to 0 + lim (\frac{2 x}{∣ x ∣})