What is (\partial)/(\partial y)(2xy+z^2) ?

The answer to (\partial)/(\partial y)(2xy+z^2) is 2x

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(\partial)/(\partial y)(2xy+z^2)

\frac{\partial}{\partial y} (2 x y + z^{2})

2 x

Solution steps

\frac{\partial}{\partial y} (2 x y + z^{2})

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (z^{2})

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (z^{2}) = 0

= 2 x + 0

Simplify

= 2 x

\frac{\partial}{\partial x} (3 x ln (y) + y ln (z) - 2 x)

\int x (x + \frac{1}{x}) d x

\int x^{2} d x

x \to 0 + lim (\frac{2 x}{∣ x ∣})

\frac{d}{d x} (x (x^{2} - 1))

What is (\partial)/(\partial y)(2xy+z^2) ?
The answer to (\partial)/(\partial y)(2xy+z^2) is 2x