What is the derivative of f(x)=(x^2-1)/(2x+2) ?

The derivative of f(x)=(x^2-1)/(2x+2) is 1/2

What is the first derivative of f(x)=(x^2-1)/(2x+2) ?

The first derivative of f(x)=(x^2-1)/(2x+2) is 1/2

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derivative of

f (x) = \frac{x ^{2} - 1}{2 x + 2}

\frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{2 x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 1 ) ( 2 x + 2 ) - \frac{d}{d x} ( 2 x + 2 ) ( x ^{2} - 1 )}{( 2 x + 2 ) ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} (2 x + 2) = 2

= \frac{2 x ( 2 x + 2 ) - 2 ( x ^{2} - 1 )}{( 2 x + 2 ) ^{2}}

Simplify

\frac{2 x ( 2 x + 2 ) - 2 ( x ^{2} - 1 )}{( 2 x + 2 ) ^{2}} : \frac{1}{2}

= \frac{1}{2}

f (x) = 4 x^{4} - 5 x^{3} + 2 x - 3

\frac{d}{d x} (\frac{x}{a ^{2} a ^{2} + x ^{2}})

\frac{d}{d x} (25 ln (x^{2}) - x^{2})

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 4)^{5})

\int_{1}^{4} x d x

What is the derivative of f(x)=(x^2-1)/(2x+2) ?
The derivative of f(x)=(x^2-1)/(2x+2) is 1/2
What is the first derivative of f(x)=(x^2-1)/(2x+2) ?
The first derivative of f(x)=(x^2-1)/(2x+2) is 1/2