derivative of (x^3/3-2x^2+3x)

Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} - 2 x^{2} + 3 x)

x^{2} - 4 x + 3

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} - 2 x^{2} + 3 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

= x^{2} - 4 x + 3

\frac{d}{d x} (- \frac{2 x}{( 9 + x ^{2} ) ^{2}})

\frac{d x}{d t} = 12 - \frac{x}{200 + 3 t}

t an g e n t f (x) = x^{3} - 3 x^{2} - 9 x + 27, at x = 4

\frac{\partial}{\partial x} (\frac{3 x + y ^{2}}{x y})

\int (5 x^{4} - 8 x^{3} + 9 x^{2} - 2 x + 7) d x