What is the integral from 0 to 2 of 1/(x^{1/3)} ?

The integral from 0 to 2 of 1/(x^{1/3)} is 3/(2^{1/3)}

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integral from 0 to 2 of 1/(x^{1/3)}

\int_{0}^{2} \frac{1}{x ^{\frac{1}{3}}} d x

\frac{3}{2 ^{\frac{1}{3}}}

Decimal Notation

2.38110 \dots

Solution steps

\int_{0}^{2} \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{2}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{2}

Compute the boundaries:

\frac{3}{2 ^{\frac{1}{3}}}

= \frac{3}{2 ^{\frac{1}{3}}}

(x^{3})^{^{'}}

f (x) = x - 3

\int 2 x^{6} d x

\int e^{2} x cos (3 x) d x

\int x^{3} e^{x^{2}} d x

What is the integral from 0 to 2 of 1/(x^{1/3)} ?
The integral from 0 to 2 of 1/(x^{1/3)} is 3/(2^{1/3)}