What is the integral of e^2xcos(3x) ?

The integral of e^2xcos(3x) is (e^2)/9 (3xsin(3x)+cos(3x))+C

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integral of e^2xcos(3x)

\int e^{2} x cos (3 x) d x

\frac{e ^{2}}{9} (3 x sin (3 x) + cos (3 x)) + C

Solution steps

\int e^{2} x cos (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{2} \cdot \int x cos (3 x) d x

Apply u-substitution

: \int \frac{u cos ( u )}{9} d u

= e^{2} \cdot \int \frac{u cos ( u )}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{2} \frac{1}{9} \cdot \int u cos (u) d u

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= e^{2} \frac{1}{9} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= e^{2} \frac{1}{9} (u sin (u) - (- cos (u)))

Substitute back

u = 3 x

= e^{2} \frac{1}{9} (3 x sin (3 x) - (- cos (3 x)))

Simplify

e^{2} \frac{1}{9} (3 x sin (3 x) - (- cos (3 x))) : \frac{e ^{2}}{9} (3 x sin (3 x) + cos (3 x))

= \frac{e ^{2}}{9} (3 x sin (3 x) + cos (3 x))

Add a constant to the solution

= \frac{e ^{2}}{9} (3 x sin (3 x) + cos (3 x)) + C

\int x^{3} e^{x^{2}} d x

\frac{\partial}{\partial x} (sin (x y z^{3}))

\int_{0}^{5} e^{3 x} d x

4 y^{^{''}} - 16 y^{^{'}} + 19 y = 0

\frac{d}{d x} (2 x^{2} cos (x))

What is the integral of e^2xcos(3x) ?
The integral of e^2xcos(3x) is (e^2)/9 (3xsin(3x)+cos(3x))+C