What is the derivative of f(x)= 1/(x^8) ?

The derivative of f(x)= 1/(x^8) is -8/(x^9)

What is the first derivative of f(x)= 1/(x^8) ?

The first derivative of f(x)= 1/(x^8) is -8/(x^9)

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derivative of

f (x) = \frac{1}{x ^{8}}

- \frac{8}{x ^{9}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{8}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 8})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 x^{- 8 - 1}

Simplify

- 8 x^{- 8 - 1} : - \frac{8}{x ^{9}}

= - \frac{8}{x ^{9}}

\frac{d}{d x} (x + \frac{1}{x})

\int 2 x + 5 d x

f (x) = - 2 x^{4}, at x = 3

\frac{d}{d r} (- arctan (r) + 2 arccot (r) - ln (r))

\int 19 d x

What is the derivative of f(x)= 1/(x^8) ?
The derivative of f(x)= 1/(x^8) is -8/(x^9)
What is the first derivative of f(x)= 1/(x^8) ?
The first derivative of f(x)= 1/(x^8) is -8/(x^9)