What is the tangent of f(x)=-2x^4,\at x=3 ?

The tangent of f(x)=-2x^4,\at x=3 is y=-216x+486

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tangent of f(x)=-2x^4,\at x=3

tangent of

f (x) = - 2 x^{4}, at x = 3

y = - 216 x + 486

Solution steps

Find the tangent point:

(3, - 162)

Find the slope of

f (x) = - 2 x^{4} : \frac{df ( x )}{d x} = - 8 x^{3}

Compute the slope of

f (x) = - 2 x^{4}

x = 3 : m = - 216

Find the line with slope m=

- 216

and passing through

(3, - 162) : y = - 216 x + 486

y = - 216 x + 486

\frac{d}{d r} (- arctan (r) + 2 arccot (r) - ln (r))

\int 19 d x

\frac{\partial}{\partial x} (2 x + 5 y)

\int 13 cos (π x) cos (4 π x) d x

n = 0 \sum \infty cos (7 πn)

What is the tangent of f(x)=-2x^4,\at x=3 ?
The tangent of f(x)=-2x^4,\at x=3 is y=-216x+486