integral of cos^6(x)sin^3(x)

Lösung

\int cos^{6} (x) sin^{3} (x) d x

- \frac{cos ^{7} ( x )}{7} + \frac{cos ^{9} ( x )}{9} + C

Schritte zur Lösung

\int cos^{6} (x) sin^{3} (x) d x

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= \int (1 - cos^{2} (x)) sin (x) cos^{6} (x) d x

Wende U-Substitution an

= \int - u^{6} (1 - u^{2}) d u

Multipliziere aus

- u^{6} (1 - u^{2}) : - u^{6} + u^{8}

= \int - u^{6} + u^{8} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int u^{6} d u + \int u^{8} d u

\int u^{6} d u = \frac{u ^{7}}{7}

\int u^{8} d u = \frac{u ^{9}}{9}

= - \frac{u ^{7}}{7} + \frac{u ^{9}}{9}

Setze in

u = cos (x)

ein

= - \frac{cos ^{7} ( x )}{7} + \frac{cos ^{9} ( x )}{9}

Füge eine Konstante zur Lösung hinzu

= - \frac{cos ^{7} ( x )}{7} + \frac{cos ^{9} ( x )}{9} + C

\int (1 - x x) d x

\int \frac{( x ^{8} + 1 )}{x ^{9} + 9 x} d x

in t e g r a l \frac{1}{1 - x ^{2}}

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