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Popular >

(-1/x)^'

Solution

(- \frac{1}{x})^{^{'}}

Solution

\frac{1}{x ^{2}}

Solution steps

(- \frac{1}{x})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - (\frac{1}{x})^{^{'}}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - (x^{- 1})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - (- 1 \cdot x^{- 1 - 1})

Simplify

- (- 1 \cdot x^{- 1 - 1}) : \frac{1}{x ^{2}}

= \frac{1}{x ^{2}}

Popular Examples

y^{''}+2y^'=2x+9-e^{-2x}

y^{^{''}} + 2 y^{^{'}} = 2 x + 9 - e^{- 2 x}

inverse oflaplace (6s+4)/(s^2+4s+20)inverse laplace

\frac{6 s + 4}{s ^{2} + 4 s + 20}

y^{^{'}} + 5 y = e^{- 3 x}

integral of sin^6(x)cos^5(x)

\int sin^{6} (x) cos^{5} (x) d x

integral of e^x+x^e+e+x

\int e^{x} + x^{e} + e + x d x

Frequently Asked Questions (FAQ)

What is the (-1/x)^' ?
The (-1/x)^' is 1/(x^2)
What is the first (-1/x)^' ?
The first (-1/x)^' is 1/(x^2)