What is the sum from n=1 to infinity of ((2pi)/3)^n ?

The sum from n=1 to infinity of ((2pi)/3)^n is diverges

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sum from n=1 to infinity of ((2pi)/3)^n

n = 1 \sum \infty (\frac{2 π}{3})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{2 π}{3})^{n}

Apply Series Ratio Test:

diverges

= diverges

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What is the sum from n=1 to infinity of ((2pi)/3)^n ?
The sum from n=1 to infinity of ((2pi)/3)^n is diverges