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Popular >

integral of 1/(8x^3)

Solution

\int \frac{1}{8 x ^{3}} d x

Solution

- \frac{1}{16 x ^{2}} + C

Solution steps

\int \frac{1}{8 x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= \frac{1}{8} (- \frac{1}{2 x ^{2}})

Simplify

\frac{1}{8} (- \frac{1}{2 x ^{2}}) : - \frac{1}{16 x ^{2}}

= - \frac{1}{16 x ^{2}}

Add a constant to the solution

= - \frac{1}{16 x ^{2}} + C

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Frequently Asked Questions (FAQ)

What is the integral of 1/(8x^3) ?
The integral of 1/(8x^3) is -1/(16x^2)+C