What is the integral from 0 to 1 of 1/(x^{1.5)} ?

The integral from 0 to 1 of 1/(x^{1.5)} is diverges

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integral from 0 to 1 of 1/(x^{1.5)}

\int_{0}^{1} \frac{1}{x ^{1.5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{x ^{1.5}} d x

Apply the Power Rule

: [- \frac{2}{x}]_{0}^{1}

= [- \frac{2}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

y = x + 1

\int 7 x^{2} e^{2 x} d x

x \to - 5 lim (\frac{5 x + 4}{x + 8})

(\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y - 5 y^{3})

\frac{\partial}{\partial x} (9 x^{2} + y^{2})

What is the integral from 0 to 1 of 1/(x^{1.5)} ?
The integral from 0 to 1 of 1/(x^{1.5)} is diverges