What is the tangent of y=2x^3-2x,(1,0) ?

The tangent of y=2x^3-2x,(1,0) is y=4x-4

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tangent of y=2x^3-2x,(1,0)

tangent of

y = 2 x^{3} - 2 x, (1, 0)

y = 4 x - 4

Solution steps

Find the slope of

y = 2 x^{3} - 2 x : \frac{d y}{d x} = 6 x^{2} - 2

Compute the slope of

y = 2 x^{3} - 2 x

(1, 0) : m = 4

Find the line with slope m=

4

and passing through

(1, 0) : y = 4 x - 4

y = 4 x - 4

x \to 0 lim (arctan (3 x))

\frac{d x}{d t} = 3 x + e^{2 t} - 2 e^{3 t} + e^{4 t}

\frac{d}{d x} (ln (\frac{7 x ^{2} + x}{x ^{2}}))

y = (\frac{x}{5 + x})

\frac{d}{d x} (e^{- 2 x} sin (2 x))

What is the tangent of y=2x^3-2x,(1,0) ?
The tangent of y=2x^3-2x,(1,0) is y=4x-4