What is integral of f(x)g(x) ?

The answer to integral of f(x)g(x) is (fgx^3)/3+C

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integral of f(x)g(x)

\int f (x) g (x) d x

\frac{f g x ^{3}}{3} + C

Solution steps

\int f xgx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f g \cdot \int xx d x

Simplify

xx : x^{2}

= f g \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= f g \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{f g x ^{3}}{3}

Add a constant to the solution

= \frac{f g x ^{3}}{3} + C

x \to \infty lim (x - 8)

\int \frac{5}{4 + x} d x

\int + cot^{2} (x) d x

\int 2 x (x^{2} + 5)^{9} d x

x \to 3 - lim (4 x^{2} - 3 x + 2)

What is integral of f(x)g(x) ?
The answer to integral of f(x)g(x) is (fgx^3)/3+C