What is the integral of+cot^2(x) ?

The integral of+cot^2(x) is -x-cot(x)+C

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integral of+cot^2(x)

\int + cot^{2} (x) d x

- x - cot (x) + C

Solution steps

\int cot^{2} (x) d x

Rewrite using trig identities

= \int - 1 + csc^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d x + \int csc^{2} (x) d x

\int 1 d x = x

\int csc^{2} (x) d x = - cot (x)

= - x - cot (x)

Add a constant to the solution

= - x - cot (x) + C

\int 2 x (x^{2} + 5)^{9} d x

x \to 3 - lim (4 x^{2} - 3 x + 2)

\int \frac{4}{x} d x

\int t (t^{2} + 1)^{4} d t

n = 1 \sum \infty cos^{n} (0.6)