What is the tangent of y=(sqrt(x))/(x+9),(1,0.1) ?

The tangent of y=(sqrt(x))/(x+9),(1,0.1) is y= 1/25 x+0.06

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tangent of y=(sqrt(x))/(x+9),(1,0.1)

tangent of

y = \frac{x}{x + 9}, (1, 0.1)

y = \frac{1}{25} x + 0.06

Solution steps

Find the slope of

y = \frac{x}{x + 9} : \frac{d y}{d x} = \frac{- x + 9}{2 x ( x + 9 ) ^{2}}

Compute the slope of

y = \frac{x}{x + 9}

(1, 0.1) : m = \frac{1}{25}

Find the line with slope m=

\frac{1}{25}

and passing through

(1, 0.1) : y = \frac{1}{25} x + 0.06

y = \frac{1}{25} x + 0.06

- 2 x^{\frac{2}{3}} - 4, at x = 8

(2 x^{2} - 4)^{3}

x \to 0 - lim (\frac{cot ( π x ) sin ( x )}{2 sec ( x )})

n = 0 \sum \infty 2 n - 1

\frac{\partial}{\partial x} (\frac{y}{x ( x + y )})

What is the tangent of y=(sqrt(x))/(x+9),(1,0.1) ?
The tangent of y=(sqrt(x))/(x+9),(1,0.1) is y= 1/25 x+0.06