What is the tangent of-2x^{2/3}-4,\at x=8 ?

The tangent of-2x^{2/3}-4,\at x=8 is y=-2/3 x-20/3

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tangent of-2x^{2/3}-4,\at x=8

tangent of

- 2 x^{\frac{2}{3}} - 4, at x = 8

y = - \frac{2}{3} x - \frac{20}{3}

Solution steps

Find the tangent point:

(8, - 12)

Find the slope of

y = - 2 x^{\frac{2}{3}} - 4 : \frac{d y}{d x} = - \frac{4}{3 x ^{\frac{1}{3}}}

Compute the slope of

y = - 2 x^{\frac{2}{3}} - 4

x = 8 : m = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(8, - 12) : y = - \frac{2}{3} x - \frac{20}{3}

y = - \frac{2}{3} x - \frac{20}{3}

(2 x^{2} - 4)^{3}

x \to 0 - lim (\frac{cot ( π x ) sin ( x )}{2 sec ( x )})

n = 0 \sum \infty 2 n - 1

\frac{\partial}{\partial x} (\frac{y}{x ( x + y )})

x \to 7 lim (\frac{x + 8}{x - 7})

What is the tangent of-2x^{2/3}-4,\at x=8 ?
The tangent of-2x^{2/3}-4,\at x=8 is y=-2/3 x-20/3