integral of (3x^5-2x^3+3)/(x^2)

Lösung

\int \frac{3 x ^{5} - 2 x ^{3} + 3}{x ^{2}} d x

\frac{3 x ^{4}}{4} - x^{2} - \frac{3}{x} + C

Schritte zur Lösung

\int \frac{3 x ^{5} - 2 x ^{3} + 3}{x ^{2}} d x

Multipliziere aus

\frac{3 x ^{5} - 2 x ^{3} + 3}{x ^{2}} : 3 x^{3} - 2 x + \frac{3}{x ^{2}}

= \int 3 x^{3} - 2 x + \frac{3}{x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{3} d x - \int 2 x d x + \int \frac{3}{x ^{2}} d x

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 2 x d x = x^{2}

\int \frac{3}{x ^{2}} d x = - \frac{3}{x}

= \frac{3 x ^{4}}{4} - x^{2} - \frac{3}{x}

Füge eine Konstante zur Lösung hinzu

= \frac{3 x ^{4}}{4} - x^{2} - \frac{3}{x} + C

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