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Popular >

(dy)/(dx)=tan^2(x)

Solution

\frac{d y}{d x} = tan^{2} (x)

Solution

y = - x + tan (x) + c_{1}

Solution steps

\frac{d y}{d x} = tan^{2} (x)

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = tan^{2} (x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int tan^{2} (x) d x

\int tan^{2} (x) d x = - x + tan (x) + c_{1}

y = - x + tan (x) + c_{1}

Popular Examples

(d^2)/(dx^2)((3x+4)/(2x-5))

\frac{d ^{2}}{d x ^{2}} (\frac{3 x + 4}{2 x - 5})

integral of 1/((cos(x))^2)

\int \frac{1}{( cos ( x ) ) ^{2}} d x

(\partial)/(\partial x)(3xsin(4x^2y))

\frac{\partial}{\partial x} (3 x sin (4 x^{2} y))

area y=3(x+1),y=4(x+1),x=3 area

y = 3 (x + 1), y = 4 (x + 1), x = 3

integral from 0 to (3pi)/2 of 2|sin(x)|

\int_{0}^{\frac{3 π}{2}} 2 ∣ sin (x) ∣ d x

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dx)=tan^2(x) ?
The solution for (dy)/(dx)=tan^2(x) is y=-x+tan(x)+c_{1}