What is the limit as z approaches 2 of (z^2+3)/(iz) ?

The limit as z approaches 2 of (z^2+3)/(iz) is -(7i)/2

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limit as z approaches 2 of (z^2+3)/(iz)

z \to 2 lim (\frac{z ^{2} + 3}{i z})

- \frac{7 i}{2}

Solution steps

z \to 2 lim (\frac{z ^{2} + 3}{i z})

Plug in the value

z = 2

= \frac{2 ^{2} + 3}{i 2}

Simplify

\frac{2 ^{2} + 3}{i 2} : - \frac{7 i}{2}

= - \frac{7 i}{2}

ln (1 + 7 x)

\frac{d ^{2}}{d x ^{2}} (4 x + 15)

\frac{\partial}{\partial x} (xx + yy)

\int_{0}^{π} x \cdot cos (x) d x

n = 0 \sum \infty \frac{1}{n ^{\frac{1}{3}}}

What is the limit as z approaches 2 of (z^2+3)/(iz) ?
The limit as z approaches 2 of (z^2+3)/(iz) is -(7i)/2