What is the integral from 0 to pi of x*cos(x) ?

The integral from 0 to pi of x*cos(x) is -2

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integral from 0 to pi of x*cos(x)

\int_{0}^{π} x \cdot cos (x) d x

- 2

Solution steps

\int_{0}^{π} x cos (x) d x

Apply Integration By Parts

: [x sin (x) - \int sin (x) d x]_{0}^{π}

= [x sin (x) - \int sin (x) d x]_{0}^{π}

\int sin (x) d x = - cos (x)

= [x sin (x) - (- cos (x))]_{0}^{π}

Simplify

= [x sin (x) + cos (x)]_{0}^{π}

Compute the boundaries:

- 2

= - 2

n = 0 \sum \infty \frac{1}{n ^{\frac{1}{3}}}

\frac{d}{d x} (- x y^{2})

\frac{9}{s ( s ^{2} + 9 s + 9 )}

f (x) = e^{x} + 1, at x = 0

f (x) = \frac{4}{x ^{5}} - \frac{1}{x ^{2}}, at x = 1

What is the integral from 0 to pi of x*cos(x) ?
The integral from 0 to pi of x*cos(x) is -2