derivative of tan(sqrt(1+x^3))

Lösung

\frac{d}{d x} (tan (1 + x^{3}))

\frac{3 x ^{2} sec ^{2} ( 1 + x ^{3} )}{2 1 + x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (tan (1 + x^{3}))

Wende die Kettenregel an:

sec^{2} (1 + x^{3}) \frac{d}{d x} (1 + x^{3})

= sec^{2} (1 + x^{3}) \frac{d}{d x} (1 + x^{3})

\frac{d}{d x} (1 + x^{3}) = \frac{3 x ^{2}}{2 1 + x ^{3}}

= sec^{2} (1 + x^{3}) \frac{3 x ^{2}}{2 1 + x ^{3}}

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 x ^{2} sec ^{2} ( 1 + x ^{3} )}{2 1 + x ^{3}}

\int_{1}^{2} \frac{13}{x ^{3} + 5 x} d x

\int 12 - 3 x^{2} d x

\int (3 - 2 t + t^{2}) d t

\int \frac{sin ( x )}{5 + cos ( x )} d x

\frac{\partial}{\partial x} (x^{2} - x yz)