integral of (3-2t+t^2)

Lösung

\int (3 - 2 t + t^{2}) d t

3 t - t^{2} + \frac{t ^{3}}{3} + C

Schritte zur Lösung

\int 3 - 2 t + t^{2} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d t - \int 2 t d t + \int t^{2} d t

\int 3 d t = 3 t

\int 2 t d t = t^{2}

\int t^{2} d t = \frac{t ^{3}}{3}

= 3 t - t^{2} + \frac{t ^{3}}{3}

Füge eine Konstante zur Lösung hinzu

= 3 t - t^{2} + \frac{t ^{3}}{3} + C

\int \frac{sin ( x )}{5 + cos ( x )} d x

\frac{\partial}{\partial x} (x^{2} - x yz)

\int (e^{y^{2}}) d y

d er i v a t i v e y = 3 x

\frac{\partial}{\partial x} (x^{6} y - 4 x^{5} y^{2})