What is the tangent of 7x^2 ?

The tangent of 7x^2 is y=14a_{0}x-7a_{0}^2

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tangent of 7x^2

tangent of

7 x^{2}

y = 14 a_{0} x - 7 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0}^{2})

Find the slope of

y = 7 x^{2} : \frac{d y}{d x} = 14 x

Compute the slope of

y = 7 x^{2}

x = a_{0} : m = 14 a_{0}

Find the line with slope m=

14 a_{0}

and passing through

(a_{0}, 7 a_{0}^{2}) : y = 14 a_{0} x - 7 a_{0}^{2}

y = 14 a_{0} x - 7 a_{0}^{2}

y = (arcsin (sec (x)))^{t a n h (x)}

\int (a x + b) d x

\frac{d}{d x} (ln (arctan (cos (x))))

\int cos (x π) d x